Basic Elements :

The Modular Display System consists of two basic elements-the node & the tube. A number of different models are available depending on criteria, such as load burden, design, place & cost, etc.

The node has 18 squares to create 18 threaded holes for practical use.

Therefore, 45^o, 60^o, 90^o, 135^o & 180^o can be achieved. 

The tubes have threaded ends on both side to introduce tensile or forces into the nodes. The length of tube is designated by the standard measure from node axis to node axis.

Tube Length :

The length of tubes increase in geometrical progression by the factor 2, i.e.

250mm x √2 = 353mm	707mm x √2 = 1000mm
353mm x √2 = 500mm	1000mm x √2 = 1414mm
500mm x √2 = 707mm	1414mm x √2 = 2000mm

By following the rule, a wide variety of tube length can be obtained, In this way, custom-made tube length are available without difficulty to meet any designing needs.

Take the cube for example, the angles of the node axes to each other are the same as the angles of the plane diagonals i.e. 45^o, 60^o, 90^o.

Counting Method of Space Frame Tubes & Nodes Required :

• Due to the structure of space frame are 3 dimension, how to count the necessary materials (tubes & nodes), some time confuse the designer. so there is a simple way to count how many materials (tubes & nodes) you needed.
• Usually, the top area is not equal to the bottom, so take the larger one as the counting base.

• A. Counting method while the tubes length are equal (see figure 1)
  
  A=6   B=3
  

  Volume of Node :

  2xAxB+(A+B+1)=2x6x3+(6+3+1)=46pcs
  

  Volume of Tube :

  8xAxB=8x6x3=144pcs
  
  
  
  
• B. Counting method while the tubes length are not equal (see figure 2)
  
  A=5  B=3
  

  Volume of Node :

  2xAxB+(A+B+1)=2x5x3+(5+3+1)=39pcs
  

  Volume of Long Tube :

  Ax(B+1)=5x(3+1)=20pcs
  Bx(A-1)=3x(5-1)=12pcs
  Total :32pcs
  

  Volume of Short Tube :

  AxBx4=5x3x4=60pcs
  Ax(B-1)=5x(3-1)=10pcs
  Bx(A+1)=3x(5+1)=18pcs
  Total : 88pcs

* Remarks : Bold line as long tube, thin line as short tube.